quadratic help -8x^2+2?
回答 (7)
2010-08-26 12:39 pm
✔ 最佳答案
-8x^2+2=-2(4x^2-1)
=-2(2x+1)(2x-1) answer//
2010-08-26 7:28 pm
a^2 - b^2 â¡ (a + b)(a - b)
-8x^2 + 2
= -2(4x^2) + (-2)(-1)
= -2(4x^2 - 1)
= -2[(2x)^2 - 1^2]
= -2(2x + 1)(2x - 1)
-8x^2 + 2
= -2(4x^2) + (-2)(-1)
= -2(4x^2 - 1)
= -2[(2x)^2 - 1^2]
= -2(2x + 1)(2x - 1)
2010-08-26 7:22 pm
Factorise:
-8x^2 + 2
Factor out the Greatest Common Factor (GCF) = 2
2(1 - 4X^2)
Factor a difference between two squares
The answer:
2(1 + 2x)(1 - 2x)
-8x^2 + 2
Factor out the Greatest Common Factor (GCF) = 2
2(1 - 4X^2)
Factor a difference between two squares
The answer:
2(1 + 2x)(1 - 2x)
2010-08-26 7:00 pm
You have
-8x^2+2
Now, taking 2 as common factor we factorize thus
2(-4x^2+1)
Taking the negative coefficient outside the bracket, we get
-2(4x^2-1)
By taking (2x)^2 instead of 4x^2 and 1^2 instead of 1, we get
-2[(2x)^2-1^2]
Now, by applying [(a+b)(a-b)=a^2-b^2], we factorize thus
-2(2x+1)(2x-1)
-------------------
That'll be your answer.
Hope I'm of any help.
-8x^2+2
Now, taking 2 as common factor we factorize thus
2(-4x^2+1)
Taking the negative coefficient outside the bracket, we get
-2(4x^2-1)
By taking (2x)^2 instead of 4x^2 and 1^2 instead of 1, we get
-2[(2x)^2-1^2]
Now, by applying [(a+b)(a-b)=a^2-b^2], we factorize thus
-2(2x+1)(2x-1)
-------------------
That'll be your answer.
Hope I'm of any help.
參考: It is Meeeeeeeeeeeee ............ :-)
2010-08-26 6:51 pm
-8x^2 + 2
-2(4x^2 - 1)
-2(2x - 1)(2x + 1)
-2(4x^2 - 1)
-2(2x - 1)(2x + 1)
2010-08-26 6:49 pm
-8x^2+2 = -2(4x^2-1)
= -2(2x+1)(2x-1)
since 4x^2-1 is a difference of 2 squares... it can still be factored out
= -2(2x+1)(2x-1)
since 4x^2-1 is a difference of 2 squares... it can still be factored out
參考: 2nd Year High School Memories
JJLJMNHS
Mrs. Logmao
2010-08-26 6:47 pm
2(1 - 4x^2)
note it is now the diff of squares
2(1 - 2x)(1 + 2x)
note it is now the diff of squares
2(1 - 2x)(1 + 2x)
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