quadratic help -8x^2+2?

-8x^2+2
=-2(4x^2-1)
=-2(2x+1)(2x-1) answer//

a^2 - b^2 ≡ (a + b)(a - b)

-8x^2 + 2
= -2(4x^2) + (-2)(-1)
= -2(4x^2 - 1)
= -2[(2x)^2 - 1^2]
= -2(2x + 1)(2x - 1)

Factorise:

-8x^2 + 2

Factor out the Greatest Common Factor (GCF) = 2

2(1 - 4X^2)

Factor a difference between two squares

The answer:

2(1 + 2x)(1 - 2x)

You have

-8x^2+2

Now, taking 2 as common factor we factorize thus

2(-4x^2+1)

Taking the negative coefficient outside the bracket, we get

-2(4x^2-1)

By taking (2x)^2 instead of 4x^2 and 1^2 instead of 1, we get

-2[(2x)^2-1^2]

Now, by applying [(a+b)(a-b)=a^2-b^2], we factorize thus

-2(2x+1)(2x-1)
-------------------

That'll be your answer.

Hope I'm of any help.

-8x^2 + 2
-2(4x^2 - 1)
-2(2x - 1)(2x + 1)

-8x^2+2 = -2(4x^2-1)
= -2(2x+1)(2x-1)


since 4x^2-1 is a difference of 2 squares... it can still be factored out

2(1 - 4x^2)
note it is now the diff of squares
2(1 - 2x)(1 + 2x)