Solve the following equation: 2^x 3^x = 21
Answer: 1.9
Please help me to solve them by clear steps n show the steps. Thanks : )
F4 Math - Exponential & Log
2010-08-23 6:12 am
回答 (5)
2010-08-23 6:36 am
✔ 最佳答案
(2x)(3x) = 216x = 21 (since an x bn = (ab)n)
x log 6 = log 21
x = log 21/log 6
= 1.9
2010-08-22 22:50:19 補充：
剛用 calculator 覆檢, 應是 1.7
log 21/log 6 係岩的, 書的 ans 有D 唔妥
參考: Myself
2010-08-23 10:44 am
書個答案錯.. 1.699180325 係正確答案
[ 已用計數機驗算 : 6^(1.699180325..) =21 ]
[ 已用計數機驗算 : 6^(1.699180325..) =21 ]
2010-08-23 6:44 am
2^x 乘以 3^x = 21
6^x = 21
log_6 21 = x
x = log21/log6
沒有問題
6^x = 21
log_6 21 = x
x = log21/log6
沒有問題
2010-08-23 6:36 am
剛用了小算盤替你複算
2^1.9 * 3^1.9
= 30.1
2^1.9 * 3^1.9
= 30.1
2010-08-23 6:24 am
2^x*3^x = 21?
收錄日期: 2021-04-15 18:09:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100822000051KK01609