Rationalization
回答 (2)
2010-08-18 6:04 pm
✔ 最佳答案
1/( 1 + sqrt 2 + sqrt 3 + sqrt 6 )=( 1 +sqrt6- sqrt 2 - sqrt 3 )/( 1 + sqrt 2 + sqrt 3 + sqrt 6 )( 1 +sqrt6 - sqrt 2 - sqrt 3 )
=( 1 - sqrt 2 - sqrt 3 + sqrt 6 )/( (1+sqrt6)^2 - (sqrt2 +sqrt3)^2 )
=( 1 - sqrt 2 - sqrt 3 + sqrt 6 )/( (1+2sqrt6+6) - (2+2sqrt6+3) )
=( 1 - sqrt 2 - sqrt 3 + sqrt 6 )/7
收錄日期: 2021-04-13 17:26:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100818000051KK00383