1. y= 1/ (3x-√x^2 -1) ans: (x- 3√x^2-1)/(3x-√x^2-1)^2 (√x^2-1)
2. y= x/ √a^2-x^2 ans: a^2/ (a^2-x^2)^3/2
3. y=√2x+√x-2 ans: 9√14/ 112
4. f(x)=(x^2-4)^3/ (3x-8)^5 f'(1)= ? ans: 27/3125
f.4 calculus differentiation
2010-08-16 2:46 am
回答 (1)
2010-08-16 10:02 pm
收錄日期: 2021-04-13 17:26:31
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