pure maths MI
回答 (2)
2010-08-13 5:01 am
✔ 最佳答案
Let P(n) be sinθ + sin3θ+...+sin(2n-1)θ=(sin^nθ)/(sinθ)When n = 1,
L.S. of P(n) = sinθ
R.S. of P(n) = sinθ/sinθ = 1
L.S. of P(n) =/= R.S. of P(n)
P(1) is not true.
Disprove.
2010-08-13 17:40:00 補充：
Then just like what I have done in http://hk.knowledge.yahoo.com/question/question?qid=7010081201659
參考: Knowledge is power.
2010-08-13 8:42 pm
The Question should be:
sinθ + sin3θ+...+sin(2n-1)θ=(sin^2(nθ))/(sinθ), where θ is not a multiple of 兀
sinθ + sin3θ+...+sin(2n-1)θ=(sin^2(nθ))/(sinθ), where θ is not a multiple of 兀
收錄日期: 2021-04-22 00:48:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100812000051KK01605