1.A test paper is divided into parts A and B.Part A carries a full marks of 66,which represent 55%of the full marks of the test paper.What are the full marks of the test paper?(請回答時列式+計算+答案thx)
2.After Vincy has drunk 16% of the juice in a bottle,there is 315ml of juice left.
a)What is the percentage of the volume of juice left?(請回答時列式+計算+答案thx)
b)What is the original volume of the juice??(請回答時列式+計算+答案thx)
3.TOcut three pieces of string of 84cm,108cm and144cm long into smaller pieces of equal length,what is the maximum length of each smaller piece of string?(請回答時列式+計算+答案thx)
thank you for your help^^
三道英文數(緊急)!!!!!
2010-08-13 1:10 am
回答 (2)
2010-08-13 1:31 am
✔ 最佳答案
1. full marks of the test paper = 66/0.55 = 120 marks2.(a) % of juice left = 1- 16%
(b) original volumn = 315/0.84 = 375 ml
3. To solve this question, we have to find out their H.C.F.
84 = 12 X 7
108= 12 X 9
144= 12 X12
Therefore, their H. C. F. is 12, that the max. length of string is 12cm
參考: me~
2010-08-13 1:26 am
１．66/（除）55%
=66/0.55
=120
The full marks of the test paper is 120 marks.
2.
(a)(1-16%)
=84%
The percentage of the volume of juice left is 84%
(b)
315/84%
=315/0.84
=375
The original volume of the juice is 375mL.
3.
呢題要搵佢H.C.F(highest common factor)（最大公因數）
用短除法
=4cm
The maxium length of each smaller piece of string is 4cm.
=66/0.55
=120
The full marks of the test paper is 120 marks.
2.
(a)(1-16%)
=84%
The percentage of the volume of juice left is 84%
(b)
315/84%
=315/0.84
=375
The original volume of the juice is 375mL.
3.
呢題要搵佢H.C.F(highest common factor)（最大公因數）
用短除法
=4cm
The maxium length of each smaller piece of string is 4cm.
收錄日期: 2021-04-13 17:26:48
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