不定積分一條!急...!!! thanks!!

∫ [e^(x)^1/3]/(x^1/2) dx
put x=u^6
then
∫ [e^(x)^1/3]/(x^1/2) dx
=6 ∫ [e^u^2](u^2) du
=3 ∫ [e^u^2](u) d(u^2)
=3 ∫ u d(e^u^2)
=3 (e^u^2)u - 3 ∫ (e^u^2) du
=3 (e^u^2)u - 3√pi/2 erfi(u)
=3 (e^x^1/3)x^(1/6) - 3√pi/2 erfi(x^1/6)