If (x+1)^2 + A(2x+3) = x^2 + 2Bx + 4B, find the values of A and B
With full step plz
Maths Question
2010-08-10 3:08 am
回答 (1)
2010-08-10 4:08 am
✔ 最佳答案
(x+1)^2+A(2x+3)=x^2+2Bx+4B(x^2+2x+1)+2Ax+3A=x^2+2Bx+4B
x^2+(2+2A)x+(1+3A)=x^2+2Bx+4B
Comparing the coefficients, we have:
2+2A=2B=>A=B-1...(1)
1+3A=4B=>1+3A=4B...(2)
Sub (1) into (2),
1+3(B-1)=4B
1+3B-3=4B
B=-2 and A=-2-1=-3
收錄日期: 2021-04-22 00:51:41
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