分解因式1題
回答 (2)
2010-08-09 7:14 pm
✔ 最佳答案
(x^2)y+xyz+x(y^2)+(y^2)z+x^2+xz+yz-y^2-x-y=z(x+y)(y+1)+xy(x+y)+(x+y)(x-y)-(x+y)
=(x+y)(z(y+1)+xy+x-y-1)
=(x+y)(y+1)(z+x-1)
2010-08-09 9:24 pm
yes , correct .
收錄日期: 2021-04-13 17:25:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100809000051KK00355