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更新1:
x-3√(x^2-1)/[3x-√(x^2-1)]^2√(x^2-1)
AMATHS
2010-08-08 9:21 pm
find dy/dx for the function.
圖片參考：http://imgcld.yimg.com/8/n/HA00002921/o/701008080061413873376400.jpg
圖片參考：http://imgcld.yimg.com/8/n/HA00002921/o/701008080061413873376400.jpg
回答 (2)
2010-08-08 11:37 pm
✔ 最佳答案
What's your model answer?2010-08-08 15:37:21 補充：
As follows:
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2010-08-08 15:41:50 補充：
Note that d(√x)/dx=1/2√x
2010-08-08 10:02 pm
dy/dx=(x〖(x^2-1)〗^((-1)/2)-3)/((〖3x-√(x^2-1))〗^2 )
dy x(x^2 - 1)^(-1/2) - 3
---- = --------------------------------
dx 〖3x - √(x^2 - 1)〗^2
2010-08-08 14:02:40 補充：
dy x(x^2 - 1)^(-1/2) - 3
---- = --------------------------------
dx 〖3x - √(x^2 - 1)〗^2
dy x(x^2 - 1)^(-1/2) - 3
---- = --------------------------------
dx 〖3x - √(x^2 - 1)〗^2
2010-08-08 14:02:40 補充：
dy x(x^2 - 1)^(-1/2) - 3
---- = --------------------------------
dx 〖3x - √(x^2 - 1)〗^2
參考: me
收錄日期: 2021-04-22 00:50:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100808000051KK00614