please explain procedure: -32 = x + 3????/?

you need to isolate the variable.
try to move the +3 to the other side, so that you will have x left only.
so.. -32 minus 3 is... -35

x = -35

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-32 = x + 3 transfer the +3 to the other side of the equation that will become
x=-32-3 the sign become opposite when it is transferred to the other side of equation
x=-35 when two signs are the same then simply add.

x + 3 = - 32
x = - 35

the equation is to be solved to find out what x is
-32 = x + 3
move 3 to the left, next to -32
when a variable is moved to the opposite side it receives an opposite sign
so 3 becomes -3

-32 - 3 = x
negative and negative = positive
therefore both numbers are to be added
becoming
-35=x
x is -35

-32 = x + 3
-32 - 3 = x + 3 - 3
-35 = x
x = -35

You have to solve for what you don't know - which is x.
Get "x" by itself by subracting 3 from each side (doing the opposite of what is being done to it)
-32=x+3
-3 -3
----------------
-35=x

-35 equals x because 3 minus 3 is zero, causing x to be alone, and -32 - 3 (in other words -32 plus negative 3 is negative 35).

-32=x + 3
first thing is to minus 3 on both sides(when you do one thing on one side of the equal sign you have to do it on the other)
then you get:
-35=x
and there you have it
its just a matter of simplifying the equation so that 'x' is standing alone on one side of the equal sign

Move the 3 to the left side by subtractin 3 to both sides
So you get -32-3=x
An easier way to write this is -32+ (-3)=x
the answer is x= -35
check your math stephen lol, its -35 not -36
ooop he fixed it nvm

-32=x+3
-3____-3

x= -35

(ignore the ____ used for spacing)