因式分解 & 解不等式 (20點)

2010-07-31 4:17 am
1. 4wx + wy – 8xz^2 + 2yz^22. p^3 – ps – st^2 + p^2t^23. ( x + y )^2 – 2( x + y) + 14. x^2 + 2xy + y^2 – 15. 5a^3 ( x – y ) + 25a ^4 (y – x )6. 18( a + b ) ^2 – 32( a + b )7. ab + 24 + 12c – 6b – 2ac – 4a 8. 20p^2 + 60pq + 45q^29. 2x – 4 over 7 不小於 – 210. 1 – 5x over – 3 小於 3

回答 (2)

2010-07-31 4:52 am
✔ 最佳答案
1. 4wx + wy – 8xz^2 + 2yz^2
= w(4x+y) - 2z^2(4x-y)2. p^3 – ps – st^2 + p^2t^2
= p(p^2 - s) - t^2 (s - p^2)
= p(p^2-s) + t^2(p^2 - s)
= (p^2-s)(p+t^2)3. ( x + y )^2 – 2( x + y) + 1
Let n = x+y
(x+y)^2 - 2(x+y) + 1
= n^2 - 2n + 1
= (n-1)^2
= (x+y-1)^24. x^2 + 2xy + y^2 – 1
= (x+y)^2 - 1
= (x+y+1)(x+y-1)5. 5a^3 ( x – y ) + 25a ^4 (y – x )
= 5a^3 (x-y) - 25a^4(x-y)
= 5a^3(x-y)(1-5a)6. 18( a + b ) ^2 – 32( a + b )
= 2(a+b)[9(a+b) - 16]
= 2(a+b)(9a+9b-16)7. ab + 24 + 12c – 6b – 2ac – 4a= ab - 4a + 12c – 2ac – 6b + 24= a(b-4) + 2c(6 – a) – 6(b-4)= a(b-4) – 6(b-4) – 2c(a-6)= (b-4)(a-6) – 2c(a-6)= (a-6)(b-4-2c)8. 20p^2 + 60pq + 45q^2= 5(4p^2 + 12pq + 9q^2)= 5[(2p)^2 + 2(2p)(3q) + (3q)^2]= 5(2p+3q)^29. (2x – 4) / 7 ≥ – 22x – 4 ≥ -142x ≥ -10x ≥ -510. (1 – 5x) / – 3 < 31-5x > -910 > 5x5x < 10x < 2
參考: Knowledge is power.
2010-07-31 4:39 am
1. 4wx + wy – 8xz^2 + 2yz^2
=w(4x+y)-2z^2(4x+y)
=(4x+y)(w-2z^2)

2. p^3 – ps – st^2 + p^2t^2
=p(p^2-s)+t^2(p^2-s)
=(p^2-s)(p+t^2)

3. ( x + y )^2 – 2( x + y) + 1
=(x+y)^2-2(x+y)(1)+1^2
=(x+y-1)^2

4. x^2 + 2xy + y^2 – 1
=(x+y)^2-1^2
=(x+y+1)(x+y-1)

5. 5a^3 ( x – y ) + 25a ^4 (y – x )
=5a^3(x-y)-25a^4(x-y)
=(5a^3-25a^4)(x-y)
=5a^3(1-5a)(x-y)

6. 18( a + b ) ^2 – 32( a + b )
=(a+b)[18(a+b)-32]

7. ab + 24 + 12c – 6b – 2ac – 4a
=12c-2ac-6b+ab+24-4a
=2c(6-a)-b(6-a)+4(6-a)
=(6-a)(2c-b+4)

8. 20p^2 + 60pq + 45q^2
=5(4p^2+12pq+9q^2)
=5(2p+3q)^2

9.我唔知你系咪
=2x – 4 over 7 不小於 – 2
=(2x-4)除6 不小於 -2

10.一樣
=1 – 5x over – 3 小於 3
=(1-5x)除-3 小於 3


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