F.4 Maths

2010-07-28 7:03 pm
(6+logx^3)/log(100x)

請列出過程
更新1:

log x = a log y = 2+a 以x來表示y

回答 (1)

2010-07-28 8:10 pm
✔ 最佳答案
(6+logx^3)/log(100x)= (6 + 3logx) / (log100 + logx)= (6 + 3logx) / (2 + logx)= 3


2010-07-28 12:41:38 補充:
log y - log x = 2+a - a

log (y/x) = 2

log (y/x) = log 100

y/x = 100

x = y/100

若補充問題與原題無關請另開新題。謝謝!


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