http://img.photobucket.com/albums/v333/suei_69/PATRICKWU.jpg?t=12801699
如圖，已三角形ABC的三條角平分線交于O點，過O作OG垂直於G,求證角BOD=角COG.
一條中二數學題 想請大家幫忙
2010-07-27 7:50 pm
回答 (1)
2010-07-27 8:18 pm
✔ 最佳答案
圖片參考：http://img.photobucket.com/albums/v333/suei_69/PATRICKWU.jpg?t=12801699
ㄥBOD
= ㄥB/2 + ㄥA/2 (ext.ㄥ)
= 90° - ㄥC/2 ..........(Since A+B+C=180)
= ㄥCOG
2010-07-27 12:19:59 補充：
Note :
ㄥBOD = ㄥABO + ㄥBAO = ㄥB/2 + ㄥA/2
收錄日期: 2021-04-21 22:16:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100727000051KK00524