1.Log base 2(x-1)+2=0
2.Log(x+2)+log4=1
3.Log(x-2)-logx=-1
4.Log base 3 (4x+3)=Log 3(2x-1)+3
Logarithmic equations
2010-07-27 6:16 am
回答 (1)
2010-07-27 6:31 am
收錄日期: 2021-04-22 00:48:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100726000051KK03586