White brass consist 60 % Cu, 25 % Zn, and 15% Ni:?

the ratio is 60 : 25 : 15

we have 1000 g Cu , 350 Zn and 200 Ni

No is the limiting metal

60 : 15 = x : 200
x = mass Cu required = 800 g
mass Cu in excess = 1000 - 800 = 200 g

25 : 15 = x : 200
x = mass Zn required = 333
mass Zn in excess = 350 - 333 = 17 g

mass white brass = 800 + 333 + 200 = 1333 g

Ratio of metal in white brass, Cu : Zn : Ni
= 60% : 25% : 15%
= 12 : 5 : 3
≈ 4 : 1.67 : 1

Ratio of metal available, Cu : Zn : Ni
= 1.00kg : 350.0g : 200.0g
= 1000 : 350 : 200
= 5 : 1.75 : 1

Comparing the ratio of metal components in white brass and available to make the alloy, it can be seen that Cu and Zn are in excess (Cu: 5 > 4, Zn: 1.75 > 1.67).

a)
Using the ratio Cu : Zn : Ni = 12 : 5 : 3 and weight of Ni in alloy = 200g,
total weight of alloy
= 200 * (12 + 5 + 3) / 3
= 200 * 20 / 3
= 4000 / 3
= 1333⅓

b)
Also, using the ratio Cu : Zn : Ni = 12 : 5 : 3 and weight of Ni in alloy = 200g,
Cu left over
= 1000 - 200 * 12 / 3
= 1000 - 800
= 200

Zn left over
= 350 - 200 * 5 / 3
= 350 - 1000 / 3
= 350 - 333⅓
= 16⅔

Ni left over
= 0