The figure below for a right angle triangle where the hypotenuse has lenght 1,
show that :
sin(A-B)=sinAcosB-sinBcosA
HINT: From the diagram sin(A-B) = X/h
Find other expressions for X and h substitute these into the above equation.
Diagram: http://s975.photobucket.com/albums/ae233/chilok008/?action=view¤t=IMG00086-20100718-1245.jpg&newest=1