Maths problem
2010-07-24 1:35 am
A n-faced regular polyhedron conisists of 2n edges and (2n-4) vertices. Find n.
回答 (2)
2010-07-24 1:48 am
✔ 最佳答案
By Euler formula :V - E + F = 2
So
(2n - 4) - 2n + n = 2
- 4 + n = 2
n = 6
P.S E=edge F=face
2010-07-24 1:55 am
vertices-edge + face= 2
so : (2n - 4) - 2n + n = 2
- 4 + n = 2
n = 6
so : (2n - 4) - 2n + n = 2
- 4 + n = 2
n = 6
收錄日期: 2021-04-27 13:20:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100723000051KK01159