解下這些方程(要有遇程)
1) 7( 1.2-k )=14k
2)3/2c = -3(3c+1)
3)-6(3-2n)=5(n-2)
4)4[3(y-20+1]= -14
5)2[a-(1=a)]=3(a-1)+8
6)2(z+1)=3(z-4)
7)5(0.8n-1)=3n
8)2x=3(1-x)-(x+1)
9) y / 6=6-4y / 3
10)3(x-0.5)-2(x-4.5)=7
11) 6 [ 2 ( 2-y)-3Y] =24
12)9(2a-1)=3[4(1+2a)-5]-8a
13)1/3(t+9)=1/3-0.5(t+3)
14)2n-5/3=n-10/9
15)x-1/2=x+1/3+1
16)7u - 4u-1/2 =21
17)2-t/4 -t =2t-3/5
解方程(中一程度)
2010-07-23 12:50 am
回答 (2)
2010-07-23 9:19 pm
or this ?
( x + 1 ) / 2 = ( x + 1 ) / 3 + 1
3 ( x + 1 ) = 2 ( x + 1 ) + 6
x + 1 = 6
x = 5
2010-07-23 13:25:02 補充：
b) (x-1)/2 = x+ 1/3 +1
x / 2 - 1 / 2 = x + 1 / 3 + 1
0 = x / 2 + 1 + 5 / 6
- 1 - 5 / 6 = x / 2
- 11 = 3x
x = - 11 / 3
Check :
( - 11 / 3 - 1 ) / 2 = - 11 / 3 + 1 / 3 + 1
=> - 7 / 3 = -10 / 3 - 3 / 3
=> - 7 / 3 = - 7 / 3
( Right . )
( x + 1 ) / 2 = ( x + 1 ) / 3 + 1
3 ( x + 1 ) = 2 ( x + 1 ) + 6
x + 1 = 6
x = 5
2010-07-23 13:25:02 補充：
b) (x-1)/2 = x+ 1/3 +1
x / 2 - 1 / 2 = x + 1 / 3 + 1
0 = x / 2 + 1 + 5 / 6
- 1 - 5 / 6 = x / 2
- 11 = 3x
x = - 11 / 3
Check :
( - 11 / 3 - 1 ) / 2 = - 11 / 3 + 1 / 3 + 1
=> - 7 / 3 = -10 / 3 - 3 / 3
=> - 7 / 3 = - 7 / 3
( Right . )
2010-07-23 6:45 am
To 001:
Q.15
x-1/2 = x+1/3+1
It may be
a) x- 1/2 = x+ 1/3 +1
or
b) (x-1)/2 = x+ 1/3 +1
For b), there is a solution.
Q.15
x-1/2 = x+1/3+1
It may be
a) x- 1/2 = x+ 1/3 +1
or
b) (x-1)/2 = x+ 1/3 +1
For b), there is a solution.
收錄日期: 2021-04-16 00:50:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100722000051KK01177