Ten moles of an ideal gas at a pressure of 8atm and with volume 10'-2m'3 are
allowed to expand isothermally(constant temperature) until the volume doubles.
What is the work done by the gas?
Ans:5.6x10'3J
這是我的想法:根據熱力學第一定律,W=P(delta)V=Px10'-2
但P不知道要代多少,請各位幫忙!若是有其他想法也可以回答!
一題理想氣體的問題
2010-07-22 9:14 pm
回答 (1)
2010-07-22 11:51 pm
✔ 最佳答案
No. of mole of gas, n = 10 molePressure, P = 8 atm = 8 X (1.013 X 10^5) Pa
Volume, V = 10^-2 m^3
By PV = nRT
nRT = [8 X (1.013 X 10^5)](10^-2) = 8104
Work done by the gas, W = S P dV
= S nRT/V dV
= 8104 S 1/V dV
= 8104 ln[V2/V1]
= 8104ln2
= 5.6 X 10^3 J
參考: Prof. Physics
收錄日期: 2021-04-19 22:50:34
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