If (x-1)(x-a) and (x-2)[2]+b are identical, find a&b
[2]= square of (x-2)
The ans is a=3, b=-1
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Quick! University Maths
2010-07-22 3:14 am
回答 (1)
2010-07-23 6:11 am
✔ 最佳答案
If (x－1)(x－a) and (x－2)^2+bare identical，find a&bSol(x－1)(x－a)=(x－2)^2+bx^2－(1+a)x+a=x^2－4x+4+b1+a=4，a=4+ba=3，a=4+ba=3，b=－1
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