(2a+b)(2a-b)-4a+1
列埋步驟俾我呀thx=]
數學factorize...help
2010-07-21 2:32 am
回答 (3)
2010-07-21 2:39 am
✔ 最佳答案
(2a+b)(2a-b)-4a+1= (4a^2 - b^2) - 4a + 1= (4a^2 - 4a + 1) - b^2= (2a - 1)^2 - b^2= (2a - 1 + b)(2a - 1 - b)= (2a + b - 1) (2a - b - 1)
2010-07-21 4:16 am
(2a+b)(2a-b)-4a+1
4a^2-b^2-4a+1
(4a^2-4a+1)-b^2
(2a-1)^2-b^2
(2a-1+b)(2a-1+b)
4a^2-b^2-4a+1
(4a^2-4a+1)-b^2
(2a-1)^2-b^2
(2a-1+b)(2a-1+b)
2010-07-21 2:36 am
(2a+b)(2a-b)-4a+1
= 4a^2 -2ab +2ab -b^2 -4a +1
= 4a^2 - b^2 -4a +1
= a^2 - b^2 + 3a^2 -4a +1
= (a+b)(a-b) + (3a-1)(a-1)
= 4a^2 -2ab +2ab -b^2 -4a +1
= 4a^2 - b^2 -4a +1
= a^2 - b^2 + 3a^2 -4a +1
= (a+b)(a-b) + (3a-1)(a-1)
收錄日期: 2021-04-21 22:13:27
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https://hk.answers.yahoo.com/question/index?qid=20100720000051KK01257