math 4

PLS solve the following simultaneous equations......

p-q+6=0--------------------(1)
3p(p/4 +1)-q+4=0-------(2)
Solve (1):
P=q-6-------------------------(3)
Sub. (3) into (2),
3 (q-6) ((q-6)/4 +1)-q+4=0
(3q-18) (q-6+2)/4-q+4=0
(3q-18)(q-2)/4-q+4=0
3q^2-6q-18q+36-4q+16=0
3q^2-28q+52=0
q=(14+2(10)^-2) /3=6.774851773
then, P=q-6=(14+2(10)^-2) /3-6=0.774851773
OR
q=(14-2(10)^-2) /3=2.55848156
then, P=q-6=(14-2(10)^-2) /3-6=-3.44151844



2010-07-19 16:40:57 補充：
^-2應該^1/2

你鐘意啦....

你話我錯咪錯囉....
怪得過有人同我答案一樣.....

算... 我自刪

Sorry..
u are wrong..