F.4Maths一問

1,Solve 4^x=10-4^x-1Let 4^(x-1) = y , then 4^x = 4y , so4y = 10 - y5y = 10y = 24^(x-1) = 24^(x-1) = 4^(1/2)x - 1 = 1/2x = 3/2
2,Simplify(3^5k+2/27^k)^1/2= { [3 ^ (5k+2)] / (27^k) } ^ (1/2)= { [3 ^ (5k+2)] / [3 ^ (3k)] } ^ (1/2)= [ 3 ^ (5k+2 - 3k) ] ^ (1/2)= [ 3 ^ (2k+2) ] ^ (1/2)= 3 ^ (k+1)

2010-07-15 15:25:41 補充：
如果無理解錯題目 , 答案 3/2 應沒錯。

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