中3數~高手~pls!

2010-07-08 11:44 pm
有2種問題

2c^2-50<<因式分解<<pls比式 / 教點做


3x-2y-7=0---------- <<<聯立方程<<都係要式
5x+4y+3=0--------


高手pls幫手!!!
更新1:

3d^2-10<<因式分解<<呢個又點~~~d左手係單數要點做?? 仲有如果係a^3+1又係因式分解~又要點做??~~thx!!!

更新2:

咁3c^3-81得唔得? b^3-8 a^3b^3+8

更新3:

d野唔記得晒啦~ - - 佢宜家比分野我做都唔記我呢d點做- -

回答 (3)

2010-07-08 11:51 pm
✔ 最佳答案
1. 2c^2-50
=2 (c^2-25)
=2 (c+5) (c-5)



2 3x-2y-7=0 ....(1)
5x+4y+3=0....(2)

(1) : 3x-2y=7
(2) ; 5x+4y = -3

(1) x 2 + (2) ,
(6x-4y ) + (5x+4y) = 2x7 -3
11x = 11
x=1
sub x=1 into (1)
3-2y = 7
-2y = 4
y= -2
2010-07-08 11:50 pm
2c^2-50
2(c^2-25)
2(c+5)(c-5)

f2
我味學聯立方程,幫唔到你!SORRY!

2010-07-08 16:19:32 補充:
3d^2-10
can not be factorized

a^3+1
(a+1)(a^2-a+1)

2010-07-08 16:21:23 補充:
identity(恆等色)
(a^3+b^3)
(a+b)(a^2-ab+b^2)

(a^3-b^3)
(a-b)(a^2+ab+b^2)

2010-07-08 16:22:35 補充:
I am f2....

2010-07-08 16:51:38 補充:
3c^3-81
3(c^3-27)
3(c-3)(c^2+6c+9)

b^3-8
(b-2)(b^2+2b+4)

a^3b^3+8
(ab)^3+2^3
(ab+2)(a^2b^2+2ab+4)

2010-07-08 16:51:55 補充:
a^3b^3+8
(ab)^3+2^3
(ab+2)(a^2b^2-2ab+4)


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