Stable High School has a total of 112 boys and girls who play sports. If the number of girls, g is 16 more than twice the number of boys, b, how many girls play sports at this high school?
Which system of equations would help you solve this problem?
math question need help?
2010-07-06 5:13 pm
回答 (5)
2010-07-06 5:16 pm
✔ 最佳答案
The system of equations is as follows:b+g=112
g=2b+16
Now we eliminate a variable and solve, like this:
b+(2b+16)=112
3b+16=112
3b=112-16=96
b=96/3=32
g=(2*32)+16=64+16=80
So there are 80 girls and 32 boys.
2010-07-07 12:16 am
32 boys 80 girls
2010-07-07 12:20 am
g=16+2b (1)
g+b=112 (2)
are the two eqn's to solve simulataneously.
Sub (1) into (2)
16+2b+b=16+3b=112
3b=96
b=96/3=32
hence, g=112-32=80
thus, no. of girls = 80 and boys = 32
g+b=112 (2)
are the two eqn's to solve simulataneously.
Sub (1) into (2)
16+2b+b=16+3b=112
3b=96
b=96/3=32
hence, g=112-32=80
thus, no. of girls = 80 and boys = 32
參考: me
2010-07-07 12:18 am
g=16+2b and g+b=112 are the equations
Plug the solution for g into the second equation:
(16+2b)+b=112
Solve for b:
16+3b=112
3b=96
b=32
Plug your value of b back into the solution for g:
g=16+2(32)
Solve for g:
g=16+64
g=80
80 girls play sports at the high school.
Plug the solution for g into the second equation:
(16+2b)+b=112
Solve for b:
16+3b=112
3b=96
b=32
Plug your value of b back into the solution for g:
g=16+2(32)
Solve for g:
g=16+64
g=80
80 girls play sports at the high school.
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