(5+x)(10-x)
回答 (6)
2010-07-01 1:30 am
2010-07-01 1:24 am
(5+x)(10-x)
=5*10-5x+10x-x*x
=x的二次方+5x+50(answer)
2010-07-01 16:07:50 補充：
(5+x)(10-x)
=5*10-5x+10x-x*x
=-x的二次方+5x+50(answer)
=5*10-5x+10x-x*x
=x的二次方+5x+50(answer)
2010-07-01 16:07:50 補充：
(5+x)(10-x)
=5*10-5x+10x-x*x
=-x的二次方+5x+50(answer)
2010-07-01 1:07 am
(5+x)(10-x)
=(5+x)(10)-(5+x)(x)
=50+10x-5x+x^2
=x^2+10x-5x+50
=x^2+5x+50
=(5+x)(10)-(5+x)(x)
=50+10x-5x+x^2
=x^2+10x-5x+50
=x^2+5x+50
2010-07-01 1:03 am
(5+x)(10-x)
5(10-x)+x(10-x)
50-5x+10x-x^2
-x^2+5x+50
2010-06-30 17:27:52 補充：
-x^2+5x+50
2010-06-30 17:31:32 補充：
-x^2+5x+50
-(x^2-5x-50)
-(x+5)(x-10)
(x+5)(10-x)
(5+x)(10-x)
Factorization
5(10-x)+x(10-x)
50-5x+10x-x^2
-x^2+5x+50
2010-06-30 17:27:52 補充：
-x^2+5x+50
2010-06-30 17:31:32 補充：
-x^2+5x+50
-(x^2-5x-50)
-(x+5)(x-10)
(x+5)(10-x)
(5+x)(10-x)
Factorization
收錄日期: 2021-04-16 00:14:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100630000051KK01021