A) 8
B) 12
C) 16
D) 32
E) 64
What is the area of a triangle whose vertices are (-4,0), (2,4), and (4,0)?
2010-06-28 12:28 pm
回答 (3)
2010-06-28 12:45 pm
✔ 最佳答案
Shifting origin to (2,4), the new coordinates of the given points are(6,4), (0,0) and (2,-4)
Area of the triangle
= (1/2) l -24 - 8 l
= 32/2
= 16
The Answer:
C) 16
2010-06-29 2:03 am
This is a triangle with one side lying on the x-axis, between vertices (-4, 0) and (4, 0).
The base length is 4 - -4 = 8.
The height is the distance of third vertex (2, 4) from x-axis, i.e. 4.
area of triangle
= ½bh
= ½ x 8 x 4
= 16
C) 16
The base length is 4 - -4 = 8.
The height is the distance of third vertex (2, 4) from x-axis, i.e. 4.
area of triangle
= ½bh
= ½ x 8 x 4
= 16
C) 16
2010-06-28 7:34 pm
1/2(2*8)=8
A
God bless you.
A
God bless you.
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