中二 maths

All's are Pythagoras' Theorem.

L2 = sqrt.(1^2+1^2) = sqrt.2
L3 = sqrt.[(sqrt.2)^2+1) = sqrt.3
L4 = sqrt.[(sqrt.3)^2+1) = sqrt.4
L5 = sqrt.[(sqrt.4)^2+1) = sqrt.5

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so you can get the pattern,

L(n) = sqrt.(n)
where n is the positive interger.

sqrt is mean square root(開方)
ie. sqrt.9 = 3

sqrt.81 = 3^2

sqrt = square root，亦即是開方的意思

L1=sqrt(1^2+1^2)=sqrt(1+1)

L2=sqrt(L1^2+1^2)=sqrt(1^2+1^2+1^2)=sqrt(2+1)

....

Ln=sqrt(n+1)

so L1000=sqrt(1000+1)=sqrt(1001)//

2010-06-28 20:46:40 補充：
睇錯SOR ,

L1=sqrt(1^2+1^2)=sqrt(1)

L2=sqrt(L1^2+1^2)=sqrt(1^2+1^2)=sqrt(2)

....

Ln=sqrt(n)

so L1000=sqrt(1000)=sqrt(1000)//

2010-06-28 22:46:06 補充：
開方呀