Differentiation

xsin(2x+y)=y^2
x{d[sin(2x+y)]/dx]+sin(2x+y)[(dx/dx)]=2y(dy/dx)
(x)[cos(2x+y)]d(2x+y)/dx+sin(2x+y)=2y(dy/dx)
(x)[cos(2x+y)(2+dy/dx)+sin(2x+y)=2y(dy/dx)
2xcos(2x+y)+xcos(2x+y)(dy/dx)+sin(2x+y)=2y(dy/dx)
[xcos(2x+y)-2y](dy/dx)=-sin(2x+y)-2xcos(2x+y)
dy/dx=[-sin(2x+y)-2xcos(2x+y)]/[xcos(2x+y)-2y]

2010-06-23 14:44:53 補充：
補充得好好
不過兩方答案都得.....

分別係 個負響上面定下面.....

補充：
Simplified
dy/dx=[-sin(2x+y)-2xcos(2x+y)]/[xcos(2x+y)-2y]

dy/dx=-[sin(2x+y)+2xcos(2x+y)]/[xcos(2x+y)-2y]

dy/dx=[sin(2x+y)+2xcos(2x+y)]/-[xcos(2x+y)-2y]

dy/dx=[sin(2x+y)+2xcos(2x+y)]/[-xcos(2x+y)+2y]

dy/dx=[sin(2x+y)+2xcos(2x+y)]/[2y-xcos(2x+y)]