how do i factor the problem 9y^2 - 1?

2010-06-16 6:00 am

haha it's late, I can't find the formula in my book. Thank you:)

回答 (6)

2010-06-16 6:13 am

✔ 最佳答案

9y^2 - 1
=3²y² - 1²
=(3y)² - 1²
=(3y + 1)(3y - 1)

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2010-06-16 9:01 am

( 3 y - 1 ) ( 3 y + 1 )

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2010-06-16 6:17 am

(9y^2 - 1)
apply rule (a^2 - b^2) = (a + b)(a - b)
(9y^2 - 1)
(3)^2 - (1)^2
= (3y + 1)(3y -1)
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2010-06-16 6:07 am

(3y-1)(3y+1)

I just did an exam today with this on it lol...

Try hard trinomials those are fun

參考: me

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2010-06-16 6:02 am

(3y+1)(3y-1)

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2010-06-16 6:01 am

(3y - 1)(3y + 1)

Have a great night! :-)

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