A human resource manager has to locate 15 clerks into 3 offices that requires 7, 5 and 3 clerks respectively. In how many ways can the 3 groups of clerks be chosen?
ans:360360
Please teach me with explanation....Thank you very much!!!
maths and stat(combination)
2010-06-15 11:13 pm
回答 (2)
2010-06-15 11:28 pm
✔ 最佳答案
首先15個人要選7個進第一間OFFICE有15C7可能性
跟住餘下8位要選5位進第二間OFFICE
有8C5可能性
跟住餘下3位要選3位進第三間OFFICE
有3C3可能性
所以總共有
15C7(8C5)(3C3)
=6435(56)
=360360
似乎你對第1課都不太熟悉
基本上M&S的PROB都要用第1課所學~~~~~
2010-06-15 11:25 pm
First of all, the manager can choose 7 clerks randomly out of 15 which has a total of 15C7 possible combinations.
Then for the remaining 8 clerks, when choosing 5 (or 3) randomly, has a total of 8C5 (or equivalently 8C3) possible combinations.
Therefore total no. of possible groups = 15C7 x 8C5 = 360360
Then for the remaining 8 clerks, when choosing 5 (or 3) randomly, has a total of 8C5 (or equivalently 8C3) possible combinations.
Therefore total no. of possible groups = 15C7 x 8C5 = 360360
參考: Myself
收錄日期: 2021-04-13 17:18:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100615000051KK00769