F.2 --cos tan sin

(cos^2 30+tan^2 60)/(sin45 cos45)
=[(√3 /2)^2+(√3)^2] / [(√2 /2)(√2 /2)]
=(3/4 +3) / (1/2)
=(15/4)(2)
=15/2

(cos^2 30+tan^2 60)/(sin45 cos45)
=[(√3 /2)^2+(√3)^2] / [(√2 /2)(√2 /2)]
=(0.75 +3) / (1/2)
=(3.75)(2)
=7.5

Do you mean (sin45cos45)/[(cos30)^2 + (tan60)^2]?
a piece of cake.....
sin45=cos45=√2/2
cos30=√3/2
tan60=√3

answer: (√2/2)(√2/2) / [(√3/2)^2 + (√3)^2]
=1/2 x 4/15 = 2/15

please concentrate in class, this is too simple.

2010-06-20 21:33:28 補充：
he was asking "求cos^2 30+tan^2 60 分之sin45 cos45" which is literally sin45cos45/(cos30)^2+(tan60)^2
"(cos^2 30+tan^2 60)/(sin45 cos45)" is equal to "sin45 cos45分之cos^2 30+tan^2 60".
This is simple Chinese 2分之1 = 1/2 not 2/1 ,are you guys retarded or what?

2010-06-20 21:38:46 補充：
There were 2 person who mistook the question and 5 retards who voted for a wrong answer and no one else had noticed the problem? Dickheads

cos^2 30+tan^2 60 分之sin45 cos45 的值
102.3654