Cant understand voltage - want help?

2010-06-12 1:16 am
Hi, I have a small hobby dc motor, it says will work from 1.5V-6V. I attached it to a AA 1.5V battery and no problem it spins away.
I also have a small solar panel, i took it outside measured the voltage on a multimeter ( scale was 0-20V ) gave a reading or around 5-6V so i hooked it up to the motor - it just about spins. How can a bigger voltage give less power??

回答 (7)

2010-06-12 1:30 am
✔ 最佳答案
The solar panel cannot generate enough power to drive the motor.

The terminate voltage of the solar panel is 5-6V. Under no load condition, the multimter will read this voltage. When there is a load there will be a current flow. The internal resistance of solar cell causes the voltage to drop in the solar cell output. Under the load of motor, the measured volatge across the solar cell is significantly lower than the no load voltage of 5-6V.

There are two solutions to this problem.
1. Use several similar solar panels in parallel to drive the motor. Each solar panel will share a portion of the loading current of the motor.
2. Use a larger solar panel that can supply the required current to the motor. Check the solar panel and motor specification for current and power in addition to voltage.
2010-06-12 1:20 am
Think of voltage as pressure and amperage as volume.
Energy, (to spin your motor), is a combination of the two, (V x A).
Your panel put out enough voltage, but a lot less amperage,
and thus less power than the battery.
2016-10-25 2:22 pm
that's certainly very confusing for a newbie to comprehend. i am going to objective to positioned it for the duration of utilising an analogy. evaluate a golf ball(mass-m) dropped from a properly of 10ft onto moist sand. it is going to create a melancholy. Now drop it from 20ft; it is going to create an better melancholy. Why? To take the ball to 10ft, you'll have executed some artwork. This manifests because the 'capacity'(kept capacity) contained in the ball. So, more advantageous the properly , more advantageous the capacity capacity. in case you are able to comprehend gravity, we are doing artwork antagonistic to gravitational stress(g) to take the ball upwards. when we drop it , the capacity receives switched over to kinetic. Now evaluate charge as equivalent of mass. (charge is a person-friendly unit and unlike mass it has polarity). round a charge there has a tendency to exist a container which attracts unlike expenses and repels like expenses. Now evaluate 2 unlike expenses. in case you commence shifting them faraway from one yet another, you'd be feeling a stress(electric powered container)which will intend to lead them to to go back at the same time. So , you'd be doing artwork antagonistic to that stress. This artwork will ensue itself because the capacity of the charged body. note the analogy between electric powered and gravitational container. the adaptation between the potentials of charged bodies is termed capacity large difference or voltage. Earth is the reference because it really is concept to have countless charge and any volume of addition or elimination of charge can don't have any result on it. in case you comprehend kinetics physics , top the following analogy may provide some perception PE= mgh V=eEd PE=capacity capacity V=voltage m=mass e=charge on the body g=gravitational container E=electric powered container h=properly d=distance
2010-06-12 7:35 am
Pick one of the other answers for best but I noticed no one mentioned measuring the voltage across the terminals with the motor connected. I'm pretty sure this will give some insight into what's going on.
2010-06-12 1:42 am
Power = VI - its the rate of change -

Voltage = potential but you need to have amperage as well
2010-06-12 1:24 am
Check out the equations for power. I^2 * R or I * V. So voltage, by itself, i.e., with a tiny amperage, will not produce enough power. You could use the solar cell to charge the battery (if it is Rechargeable) because the right voltage at a low current for a long time will charge a battery.
2010-06-12 1:22 am
Voltage is the "difference" between the polarities on the battery.

Think about it as a measure of the "pushing force" that will drive the electrons from the negative side to the positive side.


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