a rectangle of length 5x+24 metres and width x metres area is 5 sq metres .find the value of x?

The Poster above has the math process right --- but her final answer is not correct.

The Area of the Rectangle is Length X Width as follows:

(5X + 24) x (X) = 5

(5X squared) + 24X = 5

Solving the Equation: X = 1/5 or 0.2
(not 1/10 as the poster above stated)

5 x ² + 24 x - 5 = 0

( 5 x - 1 ) ( x + 5 ) = 0

x = 0.2 is acceptable

(5x + 24) * x = 5
5 x^2 + 24 x - 5 = 0

Solving the quadratic equation,
x = 0.2 or x = -5 (rejected because <0)

Value of x is 0.2.

( 5x + 24 ) x = 5

5x^2 +24 x = 5

-24 + or - sqaureroot (24^2 - 4(5)(-5))
^all divided by 2(5)

x = 1/10