F.3 maths

🎓 學業台小學及中學教育

dickyman

2010-06-08 3:21 am

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更新1:

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回答 (1)

[匿名]

2010-06-08 10:21 pm

✔ 最佳答案

1a) AB=BF=2 ( same triangle)
angle ABE+angle EBF= angleFBC+ angle EBF=90˚
so angle ABF=90˚
AF^2=AB^2+BF^2
=4+4
=8
AF=√8

b)tan angle AFB=2/2=1
angle AFB=45˚
AE=FC=3 (same triangle)
AF=√8
EF=1

EF^2+AF^2=1+8=9
AE^2=9

therefore angle EFA=90˚
angle EFB= angle EFA+ angle AFB
=90˚+45˚
=135˚

參考: 自己

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收錄日期: 2021-04-19 22:26:44
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