1, 4, 10, 20, 35..........
Find term 1000 and term 1200
A math question (sequence)
2010-06-04 9:36 am
回答 (1)
2010-06-04 9:45 am
✔ 最佳答案
general term T(n) = (1/6)n(n+1)(n+2)so T(1000)=(1/6)(1000)(1001)(1002)=167167000
T(1200)=(1/6)(1200)(1201)(1202)=288720400
2010-06-04 13:39:26 補充：
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100604000051KK00082