✔ 最佳答案
No,.(Very Connfirmed)
In the Diagram2, The ball fell off from the track after passing through the highest point.
This will not be happen.
The ball will fall down if the speed of the ball is zero.
Let the point P be the point of the ball fall down in the diagram2.
Let P.E = potential Energy
Let K.E = Kinetic Energy
Since energy is consereved.
So P.E at the highest point > P.E at P
The loss of P.E will change to K.E.
So the speed of the ball is increasing, so if the ball will not fall down from the highest
point or before.
The ball will not fall down at the rest of the loop, since the velocity of the ball will not be
zero.
This is a much complicated solving: You may Ignored it.
The ball will also left the loop and move inside the , if the contripetal force is larger than the required one.
At the highest point. The reaction force (R) given by the track to the ball will be zero and
the only force act on the ball will only be its weight. The weight will be the centripetal force of the ball.
After passing through the highest point, there will be a reaction force (R) act on the ball
again.Since the weight is always pointing downward not to the centre of the loop. So the
centripetal force cause by the weight will be decrease depends on the postion of the ball.
The (R) will then also depends on the position to provide part of the centripetal force, in
order to keep the ball have enough centripetal force.So the (R) is dependant on the
position of the ball. So the Contripetal force will not be larger than the required one.
So the ball will always on track after passing through the highest point.
Hope this can help you to solve your question/problem.
:)
