百分比+等差數列的疑問...好急!

2010-05-31 6:51 pm
T(n)=a+(n - 1)d

82 =38+(n - 1)2

n = 23 ← 我唔明 23 係點樣計到出來 /__\





9300(1+r)^10=11000 (10為次方)

(1+r)^10 =11000 除 9300

1+r = ^10_/ ̄1.182795699 ← 唔識禁機(我用CASIO fx-3650P)

1+r = 1.016929799 ← 唔識點樣計到出來

r =(曲線形等於)1.69%

回答 (1)

2010-05-31 7:17 pm
✔ 最佳答案
(1) 82 = 38 + (n - 1)2
44 = (n - 1)2
22 = n - 1
n = 23

(2) 先在計算機計出 11000 / 9300 = 1.182795699
然後按 [1][0][SHIFT][x_/ ̄][Ans][EXE]
就可以得出 1.016929799
然後, r = 0.016929799
就是大約等於 1.69%


收錄日期: 2021-04-13 17:16:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100531000051KK00334

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