✔ 最佳答案
First, you should calculate the
1. Let c and P be the specific heat capacity of soup and the power of heater respectively.
Pt=mc^T
(15)(60)( P)=(1)(c)(70-25)
so, 20P=c --------(1)
2. Let t (seconds) be the time required.
Pt=(1.5)(c)(80-20)
Pt=(1.5)(20P)(80-20) (from (1))
t=1800s
=30mins