YOu are given 25.0 cm^3 of 11.0 M hydrochloric acid. Calculate the molarity
of the newly prepared hydrochloric acid if 75.0 cm^3 of distilled water are added successively.
SS1 Chem Concentration of sol.
2010-05-29 12:14 am
回答 (1)
2010-05-29 1:47 am
✔ 最佳答案
No. of moles of HCl = 11.0 x (25.0/1000) = 0.275 molVolume of the final solution = 25 + 75 = 100 cm³ = 0.1 dm³
Molarity of the final solution = 0.275/0.1 = 2.75 M
2010-05-28 17:50:46 補充：
Alternative method:
Before adding water: M1 = 11.0 M, V1 = 25.0 cm³
After adding water: M2 = ? M, V2 = 25.0 + 75.0 = 100.0 cm³
M1V1 = M2V2
11.0 x 25.0 = M2 x 100.0
M2 = 2.75 (M)
參考: fooks
收錄日期: 2021-04-13 17:17:04
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