F.1數學問題(急!10點!)

2010-05-23 8:38 am

圖片參考:http://img25.imageshack.us/img25/5189/mathsi.png


In the figure, AGHC, AFJD, BGFE, BHID and CIJE are straight lines.

(a) Prove that a+c =∠FJE
(b) Prove that a+b+c+d+e = 180°




10點,,thx!!
更新1:

竟然有人同我一樣禁夜-v- 琴晚我2點幾先訓-v-

更新2:

回超凡學生-小朋友Vic: gd. 回kenneth: 係bo@@漏左添@@ gd.

更新3:

唸唔到邊個好d.....投票啦!

回答 (2)

2010-05-23 8:56 am
✔ 最佳答案




(a) ∠FJE=∠CAJ+∠ACJ(ext. ∠s of Δ)

=a+c



(b) ∠EFJ=b+d(ext. ∠s of Δ)

a+b+c+d+e

=(a+c)+(b+c)+e

=FJE+EFJ+FEJ

=180(∠sum of ∠)

2010-05-23 00:56:53 補充:
=∠FJE+∠EFJ+∠FEJ
==180(∠sum of Δ)
2010-06-03 10:37 am
a)根據ACJ
a+c =∠FJE(三角形外角)
b)你左面少左一點,點B

據BDF
b+d=∠JFE(三角形
外角)
∠FJE+∠JFE+e=180°(三
角形內角和)
a+c+b+d+e=180°
a+b+c+d+e=180°


收錄日期: 2021-04-23 20:29:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100523000051KK00110

檢視 Wayback Machine 備份