A math question

2010-05-19 2:05 am
draw the graph of y=3+I x^2-5x+4 I, for 5大過或等於x大過或等於0, using a scale of 2 cm to 1 unit along each axis
use your graph to find the set of values of x for which 5大過或等於y
請說明做這些時該做什麼先 please !!

回答 (1)

2010-05-19 4:04 am
✔ 最佳答案
Step 1 : Factorize x^2 - 5x + 4 = (x - 4)(x - 1), so it cuts the x - axis at x = 1 and x = 4.
Step 2: since x^2 - 5x + 4 is negative for 1< x < 4, draw the mirror image of this part of the curve about the x - axis so as to get the curve of abs(x^2 - 5x + 4).
Step 3: Translate the abs(x^2 - 5x + 4) curve upwards by 3 units to get the complete curve y = 3 + abs(x^2 - 5x + 4).
Step 4: Draw a horizontal line y = 5 to intersect the curve y = 3 + abs(x^2 - 5x + 4) at 2 points x = a and x = b. ( a < b).
So for 5 > y, x > a or x < b will be the set of values of x.
If the line y = 5 cuts the curve at 4 points x = a, b, c and d ( a< b< c< d),
the answer will be a< x < b or c< x < d.




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