直角三角型
角B=90度
AC=529cm
AB:BC=4:3
求AB and BC長
求三角型兩邊長度
2010-05-15 7:45 pm
回答 (2)
2010-05-15 8:11 pm
✔ 最佳答案
AB^2 + BC^2 = AC^2設 AB = 4k , BC = 3k ,
(4k)^2 + (3k)^2 = 529^2
16k^2 + 9k^2 = 529^2
25k^2 = 529^2
k^2 = (529^2) / 25
k = 529/5
AB = 4*529/5 = 423.2 cm
BC = 3*529/5 = 317.4 cm
2010-05-18 10:14 am
tan(a)=3/4
角a=36.87"c
//////////////////////////////
cos(a)=ab/ac
cos(36.87)=ab/529
ab=423.2cm
//////////////////////////////
sin(a)=bc/ac
sin(36.87)=bc/529
bc=317.4cm
角a=36.87"c
//////////////////////////////
cos(a)=ab/ac
cos(36.87)=ab/529
ab=423.2cm
//////////////////////////////
sin(a)=bc/ac
sin(36.87)=bc/529
bc=317.4cm
收錄日期: 2021-04-21 22:11:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100515000051KK00441