直角三角型
角B=90度
AC=529cm
AB:BC=4:3
求AB and BC長
直角三角型兩邊長度
2010-05-15 7:42 pm
回答 (2)
2010-05-15 8:38 pm
✔ 最佳答案
設AB為4k cm, BC為3k cmAB^2 + BC^2 = AC^2 (畢氏定理)
(4k)^2 + (3k)^2 = 529^2
16k^2 + 9k^2 = 279841
25k^2 = 279841
k^2 = 11193.64
k = 105.8
AB = 4(105.8) = 423.2 cm
BC = 3(105.8) = 317.4 cm
參考: Knowledge is power.
2010-05-18 10:13 am
tan(a)=3/4
角a=36.87"c
//////////////////////////////
cos(a)=ab/ac
cos(36.87)=ab/529
ab=423.2cm
//////////////////////////////
sin(a)=bc/ac
sin(36.87)=bc/529
bc=317.4cm
角a=36.87"c
//////////////////////////////
cos(a)=ab/ac
cos(36.87)=ab/529
ab=423.2cm
//////////////////////////////
sin(a)=bc/ac
sin(36.87)=bc/529
bc=317.4cm
收錄日期: 2021-04-25 17:09:58
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100515000051KK00433