If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be
2.7969
2.7874
2.4922
2.4851
confidence interval
2010-05-15 4:08 am
回答 (1)
2010-05-15 4:57 pm
✔ 最佳答案
For unknown population standard deviation, we have to use the t-distributionSince sample size is 25, degrees of freedom=24
For a confidence interval of 99%, there is 0.5% at each end of the distribution
This corresponds to a critical t value of 2.7969 [obtained by Excel formula=TINV(1%,24)]
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