數學方程問題~please~
回答 (6)
2010-05-13 5:06 pm
✔ 最佳答案
1又3分2 n -2 = 2又6分1 ->> (5/3 n) -2 =13/6
先將分母消除 2邊x 6
-> 10n-12=13
10n=25
n=2.5
2010-05-22 4:29 am
一又三分二n=5n/3
二又六分一 =13/6
(5n/3)-2=13/6
2(5n)-2(6)=13
10n-12=13
10n=25
n=25/10
n=5/2
二又六分一 =13/6
(5n/3)-2=13/6
2(5n)-2(6)=13
10n-12=13
10n=25
n=25/10
n=5/2
2010-05-13 6:53 am
5/3n-2=13/6
5/3n=13+12/6
5/3n=25/6
n=(25/6)(3/5)
n=5/2
n=2.5
5/3n=13+12/6
5/3n=25/6
n=(25/6)(3/5)
n=5/2
n=2.5
2010-05-13 6:36 am
樓一錯了！
(5/3)n-2=13/6
(5/3)n=25/6
n= 25/6 * 3/5
n=25/10
n=2.5//
(5/3)n-2=13/6
(5/3)n=25/6
n= 25/6 * 3/5
n=25/10
n=2.5//
2010-05-13 5:54 am
等於(5/3)n - 2 = 13/6
(5/3)n = (13/6) - 2
(5/3)n = (13-12)/6
n = (1/6) (3/5)
n = 1/10
(5/3)n = (13/6) - 2
(5/3)n = (13-12)/6
n = (1/6) (3/5)
n = 1/10
參考: 自己
收錄日期: 2021-04-29 15:42:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100512000051KK01466