SS1 Maths equations
回答 (4)
Solve the following simultaneous equations.
{5^x - 3 . 4^y = 1....(1)
{2 . 5^x = 7 . 4^y - 6....(2)
(2) - (1)*2 :
6 * 4^y = 7 * 4^y - 8
4^y = 8
2^2y = 2^3
2y = 3
y = 3/2
sub it to (2) :
2 * 5^x = 7*8 - 6
5^x = 25
x = 2
[(81/625)^(1/6)] * (3/5)^x = 1
[(3/5)^(4/6)] * (3/5)^x = 1
(3/5) ^ (x + 4/6) = 1 = (3/5)^0
x + 4/6 = 0
x = - 2/3
2010-05-15 13:53:01 補充:
兩題問題只做了一題,而且做錯。不明白為何會得最佳解答??!!
2010-05-16 10:59:50 補充:
eicachan , 小樹熊 :
不要緊,謝謝!!
收錄日期: 2021-04-21 22:10:50
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