(想睇清楚d要download張圖)
圖片參考：http://imgcld.yimg.com/8/n/HA00230702/o/701005090147913873398410.jpg
[20分] Maths (Urgent)
2010-05-10 4:58 am
回答 (2)
2010-05-10 5:06 am
✔ 最佳答案
6.) M_PQ = (-2+7)/(-4+10) = 5/6M_QR = (8+2)/(8+4) = 10/12 = 5/6
M_PQ = M_QR
Hence, Q,R,P collinear.
7.) M_CD = M_DE (Given)
(3-5)/(k+1) = (5-9)/(-1-3)
-2/(k+1) = 4/4
-2 = k+1
k = -3
8.) Since P lies on x-axis , s = 0,
Since Q lies on y-axis ,, h = 0
(0+3)/(r-4) = (-3+9)/(4-8)
3/(r-4) = -6/4
12 = -6r + 24
r = 2
(k+3)/(0-4) = (-3+9)/(4-8)
-(k+3)/4 = -6/4
k+3 = 6
k = 3
參考: Hope can help you^^”
2010-05-10 7:22 am
6.) M_PQ = (-2+7)/(-4+10) = 5/6
M_QR = (8+2)/(8+4) = 10/12 = 5/6
M_PQ = M_QR
Hence, Q,R,P collinear.
7.) M_CD = M_DE (Given)
(3-5)/(k+1) = (5-9)/(-1-3)
-2/(k+1) = 4/4
-2 = k+1
k = -3
8.) Since P lies on x-axis , s = 0,
Since Q lies on y-axis ,, h = 0
(0+3)/(r-4) = (-3+9)/(4-8)
3/(r-4) = -6/4
12 = -6r + 24
r = 2
(k+3)/(0-4) = (-3+9)/(4-8)
-(k+3)/4 = -6/4
k+3 = 6
k = 3
M_QR = (8+2)/(8+4) = 10/12 = 5/6
M_PQ = M_QR
Hence, Q,R,P collinear.
7.) M_CD = M_DE (Given)
(3-5)/(k+1) = (5-9)/(-1-3)
-2/(k+1) = 4/4
-2 = k+1
k = -3
8.) Since P lies on x-axis , s = 0,
Since Q lies on y-axis ,, h = 0
(0+3)/(r-4) = (-3+9)/(4-8)
3/(r-4) = -6/4
12 = -6r + 24
r = 2
(k+3)/(0-4) = (-3+9)/(4-8)
-(k+3)/4 = -6/4
k+3 = 6
k = 3
收錄日期: 2021-04-19 22:15:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100509000051KK01479