數學小學88
回答 (6)
2010-05-09 3:07 am
✔ 最佳答案
貨車每小時行 =75km單車每min行 =10m =10/1000=10000km
單車每小時行 =36km
30分鐘後兩車相距
=(75+ 36) x 1/2
= 55.5 km
2010-05-08 19:08:45 補充：
Sorry,
貨車每小時行 =75km
單車每min行 =10m
單車每小時行 =36km
30分鐘後兩車相距
=(75+ 36) x 1/2
= 55.5 km
2010-05-16 12:03 am
貨車每小時行 =75km
單車每min行 =10m =10/1000=10000km
單車每小時行 =36km
30分鐘後兩車相距
=(75+ 36) x 1/2
= 55.5 km
單車每min行 =10m =10/1000=10000km
單車每小時行 =36km
30分鐘後兩車相距
=(75+ 36) x 1/2
= 55.5 km
2010-05-09 6:31 am
貨車以75㏎/h = 75*30/60 = 37.5kM
單車以10m/s = 10*60*30/1000 = 18kM
= 37.5+18=55.5
30分鐘後兩車相距 = 55.5kM
單車以10m/s = 10*60*30/1000 = 18kM
= 37.5+18=55.5
30分鐘後兩車相距 = 55.5kM
2010-05-09 3:13 am
Let O be the Origin,
Let point A be the lolly due to East,
Let point B be the bicycle due to West.
So AOB is a straight Line,
OA = 75kmh^-1 constantly 30min,
so OA = 37.5km
OB = 10ms^-1 constantly 30min,
so OB = 18km
Since AB = AO+OB,
So Therefore,AB = 55.5km,
So The distance between The lolly and the bicycle is 55.5km.
Let point A be the lolly due to East,
Let point B be the bicycle due to West.
So AOB is a straight Line,
OA = 75kmh^-1 constantly 30min,
so OA = 37.5km
OB = 10ms^-1 constantly 30min,
so OB = 18km
Since AB = AO+OB,
So Therefore,AB = 55.5km,
So The distance between The lolly and the bicycle is 55.5km.
2010-05-09 1:45 am
貨車每小時行 75公里,
單車每小時行 10m x 60秒 x 60分鐘 = 36000米, 即是 36公里每小時,
30分鐘後, 應是 (75+ 36) x 30/60 = 55,5 公里.
是不是這樣...
單車每小時行 10m x 60秒 x 60分鐘 = 36000米, 即是 36公里每小時,
30分鐘後, 應是 (75+ 36) x 30/60 = 55,5 公里.
是不是這樣...
收錄日期: 2021-04-13 17:14:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100508000051KK01000